Chemical EquilibriumHard
Question
ΔfGo are 30.426 kJ/mol for trans-1,2- dichloroethene and 22.112 kJ/mol for cis-1,2-dichloroethene, at 27oC. The molar ratio of trans to cis isomers at equilibrium at 27oC, is [ln28 = 3.33]
Options
A.10: 3
B.3: 10
C.28: 1
D.1: 28
Solution
$trans \rightleftharpoons Cis;\Delta G^{o} = 22.112 - 30.426 = - 8.314\text{ KJ}$
$\text{Now, }\Delta G^{o} = - RT.\ln\frac{\lbrack Cis\rbrack}{\lbrack trans\rbrack} $$${\Rightarrow - 8.314 \times 10^{3} = - 8.314 \times 300 \times \ln\frac{\lbrack Cis\rbrack}{\lbrack trans\rbrack} }{\therefore\frac{\lbrack Cis\rbrack}{\lbrack trans\rbrack} = \frac{28}{1}}$$
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