Chemical EquilibriumHard
Question
Steam decomposes at high temperature according to the following equation.
2H2O(g) $\rightleftharpoons$2H2(g) + O2(g); ΔHo = 240 kJ/ mole and ΔS° = 50 JK–1/mole
The temperature at which the equilibrium constant (KPo) becomes 1.0 is
Options
A.4.8 K
B.4800 K
C.480 K
D.impossible
Solution
$\Delta G^{o} = - 2.303RT.\ln K_{P}^{o}$
$\Delta H^{o} - T.\Delta S^{o} $$${\text{Or, } - 2.303 \times 8.314 \times T \times \ln 1.0 = 240 \times 10^{3} - T \times 50 }{\therefore T = 4800\text{ K}}$$
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