Chemical EquilibriumHard
Question
In the system, LaCl3(s) + H2O(g) + heat$\rightleftharpoons$LaClO(s) + 2HCl(g), equilibrium is established. More water vapour is added to disturb the equilibrium. If the pressure of water vapour at new equilibrium is double that of at initial equilibrium, the factor by which pressure of HCl is changed is
Options
A.2 times
B.$\sqrt{2}$ times
C.$\frac{1}{\sqrt{2}}$ times
D.4 times
Solution
$\frac{P_{H_{2}O(g)}}{P_{HCl(g)}^{2}} = \frac{P_{H_{2}O(g)} \times 2}{P_{HCl(g)}^{2},\text{ new}} \Rightarrow P_{HCl(g),\text{ new}} = \sqrt{2} \times P_{HCl(g)}$
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