Chemical EquilibriumHard
Question
PCl5(g) $\rightleftharpoons$PCl3(g) + Cl2(g). In the above reaction, the partial pressure of PCl3, Cl2 and PCl5 are 0.3, 0.2 and 0.6 atm, respectively. If partial pressure of PCl3 and Cl2 was increased twice at the new equilibrium, then what will be the new partial pressure of PCl5 (in atm)?
Options
A.0.3
B.1.2
C.2.4
D.0.15
Solution
Kp =$\frac{P_{PCl_{3}}.P_{Cl_{2}}}{P_{PCl_{5}}}$= Constant
If $P_{PCl_{3}}' = 2 \times P_{PCl_{3}}$ and $P_{Cl_{2}}' = 2 \times P_{Cl_{2}}$ then $P_{PCl_{5}}' = 4 \times P_{PCl_{5}}$.
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
For the gas phase reaction 2NO(g) $\rightleftharpoons$N2(g) + O2(g); ΔH = – 43.5 kcal. Which one of the following is tru...For the reaction CO(g) + H2O(g) ⇋ CO2(g) + H2(g) at a given temperature the equilibrium amount of CO2 (g) can be i...In the system, LaCl3(s) + H2O(g) + heat ⇋ LaClO(s) + 2HCl(g), equilibrium is established. More water vapour is add...The equilibrium mixture for the reaction 2H2S(g)$\rightleftharpoons$ 2H2(g) + S2(g) has 1 mole of H2S, 0.20 mole of H2 a...Consider the following liquid - vapour equilibrium. Liquid ⇌ Vapour Which of the following relations is correct?...