The reaction ZnO(s) + CO(g) $\rightleftharpoons$Zn(g) + CO2(g) has an equilibrium constant of 1 atm

Question

The reaction ZnO(s) + CO(g) $\rightleftharpoons$Zn(g) + CO2(g) has an equilibrium constant of 1 atm at 1500 K. The equilibrium partial pressure of zinc vapour in a reaction vessel if an equimolar mixture of CO and CO2 is brought into contact with solid ZnO at 1500 K and the equilibrium is achieved at 1 atm is

Accepted Answer

ZnO(s) + CO(g) $\rightleftharpoons$ Zn(g) + Co₂(g); K_p = 1 atm

a atm 0 a atm

Equilibrium a – x x a + x

$K_{p} = \frac{P_{Zn}.P_{CO_{2}}}{P_{CO}} \Rightarrow 1 = \frac{x(a + x)}{a - x}$

and (a – x) + x + (a + x) = P_total = 1 atm ∴ x = 0.24

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