Chemical EquilibriumMedium

Question

ΔG° for the reaction X + Y$\rightleftharpoons$C is – 4.606 kcal at 1000 K. The equilibrium constant for the reverse mode of the reaction is

Options

A.100
B.10
C.0.01
D.0.1

Solution

$\Delta G^{o} = - 2.303RT.\log K_{eq}$

Or, $- 4.606 = - 2.303 \times \frac{2}{1000} \times 1000 \times \log K_{eq} \Rightarrow K_{eq} = 10$

For reverse reaction, $K_{eq}' = \frac{1}{10} = 0.1$

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