Chemical EquilibriumMedium

Question

The equilibrium mixture for the reaction 2H2S(g)$\rightleftharpoons$ 2H2(g) + S2(g) has 1 mole of H2S, 0.20 mole of H2 and 0.80 mole of S2 in a 2 L vessel. The value of KC for the reaction is

Options

A.0.16 M
B.0.008 M
C.0.016 M
D.0.032 M

Solution

$K_{C} = \frac{\left\lbrack H_{2} \right\rbrack^{2}\left\lbrack S_{2} \right\rbrack}{\left\lbrack H_{2}S \right\rbrack^{2}} = \frac{\left( \frac{0.2}{2} \right)^{2} \times \left( \frac{0.8}{2} \right)}{\left( \frac{1}{2} \right)^{2}} = 0.016\text{ M}$

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