The equilibrium mixture for the reaction 2H2S(g)$\rightleftharpoons$ 2H2(g) + S2(g) has 1 mole of H2

Question

The equilibrium mixture for the reaction 2H2S(g)$\rightleftharpoons$ 2H2(g) + S2(g) has 1 mole of H2S, 0.20 mole of H2 and 0.80 mole of S2 in a 2 L vessel. The value of KC for the reaction is

Accepted Answer

$K_{C} = \frac{\left\lbrack H_{2} ightbrack^{2}\left\lbrack S_{2} ightbrack}{\left\lbrack H_{2}S ightbrack^{2}} = \frac{\left( \frac{0.2}{2} ight)^{2} 	imes \left( \frac{0.8}{2} ight)}{\left( \frac{1}{2} ight)^{2}} = 0.016	ext{ M}$

Question

Options

Solution

More Chemical Equilibrium Questions