Redox and Equivalent ConceptHard

Question

A quantity of 0.5 g of a metal nitrate gave 0.43 g of metal sulphate.

Options

A.The equivalent weight of the metal is 38.
B.The equivalent weight of the metal is 76.
C.The atomic weight of metal may be 76.
D.The atomic weight of metal may be 19.

Solution

neq metal nitrate = neq metal sulphate

Or $\frac{0.5}{E_{M} + 62} = \frac{0.43}{E_{M} + 48} \Rightarrow E_{M} = 38$

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