Redox and Equivalent ConceptHard
Question
A quantity of 0.5 g of a metal nitrate gave 0.43 g of metal sulphate.
Options
A.The equivalent weight of the metal is 38.
B.The equivalent weight of the metal is 76.
C.The atomic weight of metal may be 76.
D.The atomic weight of metal may be 19.
Solution
neq metal nitrate = neq metal sulphate
Or $\frac{0.5}{E_{M} + 62} = \frac{0.43}{E_{M} + 48} \Rightarrow E_{M} = 38$
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
The equivalent weight of H2SO4 in the reaction: 2KMnO4 + 3H2SO4 + 10HCl → 2MnSO4 + K2SO4 + 5Cl2 + 8H2O, is...Equivalent weight of K2CrO4 when it reacts with AgNO3 to give Ag2CrO4 is...1 g of the carbonate of a metal was dissolved in 25 mL of 1N-HCl. The resulting liquid required 5 mL of 1N-NaOH for natu...For the reaction I- + CIO3- + H2SO4 → Cl- + HSO4- + I2 The correct statements(s) in the balanced equation is/are...Equivalent weight of a metal is 18.67. When it reacts with chlorine, the mass of metal which will form 162.52 g of metal...