Redox and Equivalent ConceptHard

Question

A metal exhibits the valencies of 2 and 3. Its equivalent weight is 28 when it forms a metal oxide of formula MO. What mass of H2SO4 is needed for complete reaction with 4.8 g of M2O3?

Options

A.8.82 g
B.4.41 g
C.13.23 g
D.11.03 g

Solution

$28 = \frac{A_{M}}{2} \Rightarrow$Atomic mass of metal, AM = 56.

Now, neqH2SO4 = neqM2O3

Or $\frac{w}{98} \times 2 = \frac{4.8}{160} \times 6 \Rightarrow w = 8.82g$

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