Redox and Equivalent ConceptHard

Question

A small amount of CaCO3 completely neutralizes 525 ml of 0.1 N-HCl and no acid is left at the end. After converting all calcium chloride to CaSO4, how much plaster of Paris can be obtained?

Options

A.1.916 g
B.5.827 g
C.3.57 g
D.3.81 g

Solution

$n_{eq}HCl = n_{eq}CaSO_{4}.\frac{1}{2}H_{2}O$

Or $\frac{525 \times 0.1}{1000} = \frac{w}{145} \times 2 \Rightarrow w = 3.81\text{ g}$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions

Sulphide ions react with Na4[Fe(NO)(CN)5] to form a purple-coloured compound Na4[Fe(CN)5(NOS)]. In the reaction, the oxi...When 0.91 g of a mixture of Na2SO4 and (NH4)2SO4 was boiled with 80 ml of 0.1 N-NaOH until no more NH3 is evolved, the e...In which of the following reactions H2O2 acts as a reducing agent? (a) H2O2 + 2H+ + 2e- → 2H2O (b) H2O2 - 2e- &#85...The equivalent weight of NaHC2O4 in reaction with NaOH is...The specific heat of a metal is found to be 0.03. 10 g of the metal on treatment with nitric acid gave 18.9 g of pure dr...