Redox and Equivalent ConceptHard
Question
A small amount of CaCO3 completely neutralizes 525 ml of 0.1 N-HCl and no acid is left at the end. After converting all calcium chloride to CaSO4, how much plaster of Paris can be obtained?
Options
A.1.916 g
B.5.827 g
C.3.57 g
D.3.81 g
Solution
$n_{eq}HCl = n_{eq}CaSO_{4}.\frac{1}{2}H_{2}O$
Or $\frac{525 \times 0.1}{1000} = \frac{w}{145} \times 2 \Rightarrow w = 3.81\text{ g}$
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