Redox and Equivalent ConceptHard

Question

A volume of 50 ml of 0.1 M metal salt reacts completely with 25 ml of 0.1 M sodium sulphite. In the reaction, SO32− is oxidized to SO42−. If the oxidation number of metal in the salt is +3, then what is its new oxidation number?

Options

A.0
B.+1
C.2
D.4

Solution

neq metal salt = neq Na2SO3

Or $\frac{50 \times 0.1}{1000} \times (3 - x) = \frac{25 \times 0.1}{1000} \times 2 \Rightarrow x = 2$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions

Potassium sulphate is isomorphous with potassium chromate which contains 26.79% by mass of chromium. The atomic mass of ...The oxide of an element contains 67.67% oxygen and the vapor density of its volatilechloride is 79. Equivalent weight of...The oxidation number of S in (CH3)2SO is...The equivalent weight of ozone behaving as an oxidizing agent is...A quantity of 0.5 g of a metal nitrate gave 0.43 g of metal sulphate....