Mole ConceptHard
Question
An unknown volume of 40% (w/w) NaOH solution of specific gravity 1.6 is diluted until the specific gravity of the solution becomes 1.1. The strength of the resulting solution is
Options
A.12.8% (w/v)
B.10.67% (w/v)
C.11.6% (w/w)
D.9.7% (w/w)
Solution
$\left( V_{1} \times 16 \right) \times \frac{40}{100} = \left( V_{1} + V_{2} \right) \times 1.1 \times \frac{x}{100}$
and V1× 1.6 + V2 × 1.0 = (V1 + V2) × 1.1
∴ Strength of final solution, x = 9.7% (w/w) and 10.67% (w/v).
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