Mole ConceptHard
Question
A sample of oleum is labelled as 112%. In 200 g of this sample, 18 g water is added. The resulting solution will contain
Options
A.218 g pure H2SO4
B.218 g H2SO4 and 6 g free SO3
C.212 g H2SO4 and 6 g free SO3
D.191.33 g H2SO4 and 26.67 g free SO3
Solution
Resulting oleum is still requiring (24 – 18) = 6 g of water.
H2O + SO3 → H2SO4
18 g 80 g
∴ 6 g 26.67 g
Final composition: SO3 = 26.67 g and H2SO4 = 218 − 26.6 = 191.33 g
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
While resting, an average 70 kg human male consumes 16.628 L of oxygen per hour at 270C and 100 kPa. How many moles of o...Which of the following is/are examples of uni molecular reactions ?...The Ksp of Ag2CrO4, AgCl, AgBr and AgI are respectively, 1.1 × 10-12, 1.8 × 10-10,. 5.0 × 10-13, 8.3 ...The ratio of mass percentage $(w/w)$ of $C:H$ in a hydrocarbon is $12:1$. It has two carbon atoms. The weight (in g ) of...Hydrazine N2H4 (used as a fuel in rocket system) can be produced according to the following reaction.ClNH2 + 2NH3 → N2H4...