Mole ConceptHard
Question
A quantity of 1 kg of 2 m urea solution is mixed with 2 kg of 4 m urea solution. The molality of the resulting solution is
Options
A.3.33 m
B.10 m
C.3.29 m
D.5 m
Solution
$2 = \frac{x \times 1000}{60 \times (1000 - x)}\text{ and }4 = \frac{y \times 1000}{60 \times (2000 - y)}$
∴ Molality of resulting solution $= \frac{(x + y) \times 1000}{60 \times \left\lbrack 3000 - (x + y) \right\rbrack} = 3.29\text{ m}$
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