Mole ConceptHard
Question
A volume of 200 ml of oxygen is added to 100 ml of a mixture containing CS2 vapour and CO, and the total mixture is burnt. After combustion, the volume of the entire mixture is 245 ml. Calculate the volume of the oxygen that remains
Options
A.67.5 ml
B.125.0 ml
C.200.0 ml
D.100.0 ml
Solution
$CS_{2} + 3O_{2} \rightarrow CO_{2} + 2SO_{2}$
V mL 3V mL V mL 2V mL
2CO + O2 → 2CO2
$$(100 - V)\text{mL} \frac{1}{2}(100 - V)\text{mL} (100 - V)\text{mL}$$
Total contraction in volume, $V + \frac{1}{2}(100 - V) = (100 + 200) - 245 \Rightarrow V = 10$.
Hence, the volume of O2 remained $= 200 - \left\lbrack 3V + \frac{1}{2}(100 - V) \right\rbrack = 125\text{ mL}$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
If ‘JAYARAO BANDA’ is written by a graphite pencil, it weighs 3.0 × 10–10 g. How many carbon atoms are present in it? (N...The fractional abundance of Cl35 in a sample of chlorine containing only Cl35 (atomic weight = 34.9) and Cl37 (atomic we...When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2: 1, the ...A quantity of 2.0 g of a triatomic gaseous element was found to occupy a volume of 448 ml at 76 cm of Hg and 273 K. The ...Mole fraction of the solute in a 1.00 molal aqueous solution is...