Mole ConceptHard
Question
From the following reactions, 2CoF2 + F2 → 2CoF3 ,(CH2)n + 4n CoF3 → (CF2)n + 2n HF + 4n CoF2 calculate how much F2 will be consumed to produce 1 kg of (CF2)n. (F = 19)?
Options
A.1.52 kg
B.2.04 kg
C.0.76 kg
D.4.56 kg
Solution
1 mole of F2 ≡ 2 mole of CoF3 ≡$\frac{1}{2n}$ mole (CF2)n
= 38 g =$\frac{1}{2n} \times 50n$= 25 g
∴ Mass of F2 needed = $\frac{38}{25} \times 1$ = 1.52 kg
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