Mole ConceptHard
Question
100 gm impure CaCO3 on heating gives 5.6 lt. CO2 gas at STP. Find the percentage of calcium in the lime stone sample. [At. wt. Ca = 40 ; C = 12 ; O = 16]
Options
A.10
B.20
C.1
D.30
Solution
CaCO3 → CaO + CO2
mole
mole of CaO = mole of Ca =
mass of Ca =
× 40 = 10
% of Ca in sample =
× 100 = 10%
molemole of CaO = mole of Ca =
mass of Ca =
× 40 = 10% of Ca in sample =
× 100 = 10%Create a free account to view solution
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