Mole ConceptHard

Question

Assuming that 1,3,5-hexatriene has only pure double bonds and pure single bonds, how many grams of it contain one mole of double bonds?

Options

A.13.3 g
B.26.7 g
C.40 g
D.80 g

Solution

CH2 = CH – CH = CH – CH = CH2

For 1 mole double bond, $\frac{1}{3}$mole = $\frac{1}{3}$× 80 = 26.7 g compound is needed.

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