Mole ConceptMedium
Question
Hydrazine N2H4 (used as a fuel in rocket system) can be produced according to the following reaction.
ClNH2 + 2NH3 → N2H4 + NH4Cl
When 1.0 kg ClNH2 is reacted with excess of NH3, 473 g of N2H4 is produced. What is the percentage yield?
Options
A.76.12
B.67.21
C.26.17
D.16.72
Solution
Theoretical yield of N2H4 = $\frac{32}{51.5} \times 1000$ = 621.36 g.
Hence, the percentage yield =$\frac{473}{621.36} \times 100$= 76.12%
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