Mole ConceptHard
Question
The weight of 1 L of ozonised oxygen at STP was found to be 1.5 g. When 100 mL of this mixture at STP was treated with turpentine oil, the volume was reduced to 90 mL. The molecular weight of ozone is
Options
A.49
B.47
C.46
D.47.9
Solution
Volume of O3 in 100 mL of ozonised O2 = 100 - 90 = 10 mL (dissolved in turpentine)
Volume of O3 in 1 L of ozonised O2 =
= 100 mL
Volume of O2 in 1 L = 1000 - 100 = 900 mL
Weight of 900 mL of O2 at STP =
= 1.286 g
Weight of 100 mL of O3 at STP = 1.5 - 1.286 = 0.214 g
Now 100 mL of O3 at STP weighs = 0.21 g
for Ozone (0.21/M)×22400= 100
Molecular weight of O3(M) = 47.49
Volume of O3 in 1 L of ozonised O2 =
= 100 mLVolume of O2 in 1 L = 1000 - 100 = 900 mL
Weight of 900 mL of O2 at STP =
= 1.286 gWeight of 100 mL of O3 at STP = 1.5 - 1.286 = 0.214 g
Now 100 mL of O3 at STP weighs = 0.21 g
for Ozone (0.21/M)×22400= 100
Molecular weight of O3(M) = 47.49
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
In a hydrocarbon, mass ratio of hydrogen and carbon is 1 : 3, The empirical formula of hydrocarbon is...If NA is Avogadro′s number then number of valence electrons in 4.2 g of nitride ions (N3-)...Which of the following statement(s) is/are correct about the Avogadro’s number?...The volume strenght of 1.5 N H2O2 solution is :...When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2: 1, the ...