Mole ConceptMedium
Question
On heating KClO3 at a certain temperature, it is observed that one mole of KClO3 yields one mole of O2. What is the mole fraction of KClO4 in the final solid mixture containing only KCl and KClO4, the latter being formed by parallel reaction?
Options
A.0.50
B.0.25
C.0.33
D.0.67
Solution
2KClO3(s) → 2KCl(s) + 3O2(g)
2/3 mole 2/3 mole 1 mole
4KClO3(s) → 3KClO4(s) + KCl(s)
1/3 mole 1/4 mole 1/12 mole
Mole fraction of KClO4 = $\frac{1/4}{1/4 + (2/3 + 1/12)} = 0.25$
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