Mole ConceptMedium
Question
While resting, an average 70 kg human male consumes 16.628 L of oxygen per hour at 270C and 100 kPa. How many moles of oxygen are consumed by the 70 kg man while resting for 1 hour?
Options
A.0.67
B.66.7
C.666.7
D.67.5
Solution
$n = \frac{PV}{RT} = \frac{100 \times 10^{3} \times 16.628 \times 10^{- 3}}{8.314 \times 300} = 0.67$
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