While resting, an average 70 kg human male consumes 16.628 L of oxygen per hour at 270C and 100 kPa.

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While resting, an average 70 kg human male consumes 16.628 L of oxygen per hour at 270C and 100 kPa. How many moles of oxygen are consumed by the 70 kg man while resting for 1 hour?

Accepted Answer

$n = \frac{PV}{RT} = \frac{100 	imes 10^{3} 	imes 16.628 	imes 10^{- 3}}{8.314 	imes 300} = 0.67$

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