Mole ConceptHard

Question

What mass of solid ammonium carbonate H2NCOONH4 when vaporized at 273OC will have a volume of 8.96 L at 760 mm of pressure? Assume that the solid completely decomposes as H2NCOONH4(s) → CO2(g) + 2NH3(g)

Options

A.15.6 g
B.5.2 g
C.46.8 g
D.7.8 g

Solution

Total moles of gases = $\frac{1 \times 8.96}{0.0821 \times 546} = 0.2$

Hence, the mass of ammonium carbonate $\frac{78}{3} \times 0.2 = 5.2\text{ g}$

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