Mole ConceptMedium
Question
From 2 mg calcium, 1.2 × 1019 atoms are removed. The number of g-atoms of calcium left is (Ca = 40)
Options
A.5 × 10–5
B.2 × 10–5
C.3 × 10–5
D.5 × 10–6
Solution
Number of g-atoms left = $\frac{2 \times 10^{- 3}}{40} - \frac{1.2 \times 10^{19}}{6.0 \times 10^{23}} = 3 \times 10^{- 5}$
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