Mole ConceptHard
Question
Total number of valence electrons present in 6.4 g peroxides ion (O2 2–) is
Options
A.0.2NA
B.3.2NA
C.3.6NA
D.2.8NA
Solution
Number of valence electrons $= (2 \times 6 + 2) \times \frac{6.4}{32} \times N_{A} = 2.8N_{A}$
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