Mole ConceptMedium
Question
14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K .
Which of the following statements is incorrect?
[Given : Molar mass in $g{mol}^{- 1}$ of $Ca - 40,Cl - 35.5,H - 1$ ]
Options
A.$0.35\text{ }mol{of}_{2}$ gas is evolved.
B.$7.84{\text{ }L}^{\circ}$ of $H_{2}$ gas is evolved.
C.33.3 of ${CaCl}_{2}$ is produced.
D.The limiting reagent is calcium metal.
Solution
$\underset{\frac{14}{40}}{{Ca}_{(s)}} + \underset{\text{~excess~}}{{HCl}_{(g)}} \longrightarrow \overset{{CaCl}_{2(\text{ }s)}}{-} + \overset{H_{2(\text{ }g)}}{-}$
$= 0.35$ mole $\ 0.35$ mole 0.35 mole
Volume of $H_{2(\text{ }g)}$ evolved $= 0.35 \times 22.4 = 7.84\text{ }L$
(3) is wrong because weight of ${CaCl}_{2} = .35 \times 111 =$ 38.85 gm
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