Mole ConceptHard
Question
A gaseous mixture contains 40% H2 and 60% He by volume. What is the total number of moles of gases present in 10 g of such mixture?
Options
A.5
B.2.5
C.3.33
D.3.125
Solution
Average molar mass of the mixture =$\frac{40 \times 2 + 60 \times 4}{100} = 3.125$
Number of moles of gases present = $\frac{10}{3.2} = 3.125$
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