Atomic StructureEasy
Question
The orbital angular momentum of a 4p electron will be
Options
A.$4.\frac{h}{2\pi}$
B.$\sqrt{2}\frac{h}{2\pi}$
C.$\sqrt{6}\frac{h}{4\pi}$
D.$\sqrt{2}\frac{h}{4\pi}$
Solution
For p-orbital, $l$ = 1
∴ Orbital angular momentum $= \sqrt{l(l + 1)}.\frac{h}{2\pi} = \sqrt{1(1 + 1)}.\frac{h}{2\pi} = \sqrt{2}.\frac{h}{2\pi}$
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