Atomic StructureEasy
Question
The momentum of a photon of wavelength 6626 nm will be
Options
A.10–28 kg ms–1
B.10–25 kg ms–1
C.10–31 kg m–1
D.zero
Solution
$p = \frac{h}{\lambda} = \frac{6.626 \times 10^{- 34}}{6626 \times 10^{- 9}} = 10^{- 28}\text{ Kgm}\text{s}^{- 1}$
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