Atomic StructureHard
Question
Ionisation energy of He+ is 19.6 × 10-18 J atom-1. The energy of the first stationary state (n = 1) of Li2+ is
Options
A.4.41 × 10-16 J atom-1
B.- 4.41 × 10-17 J atom-1
C.- 2.2 × 10-15 J atom-1
D.8.82 × 10-17 J atom-1
Solution
IEHe+ = 13.6 Z2He+ 
= 13.6 Z2He+ where (Z2He+ = 2)
Hence, 13.6 × Z2He+ = 19.6 × 10-18 J atom-1
(E1)Li++ = - 13.6 Z2Li+2 x
= 13.6 Z2He+ ×
×19.6 × 10-18 × 
= 4.41 × 10-17 J atom-1
= 13.6 Z2He+ where (Z2He+ = 2)Hence, 13.6 × Z2He+ = 19.6 × 10-18 J atom-1
(E1)Li++ = - 13.6 Z2Li+2 x
= 13.6 Z2He+ × ×19.6 × 10-18 × = 4.41 × 10-17 J atom-1
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