Atomic StructureEasy
Question
The potential energy of electron revolving in the ground state of H atom is
Options
A.–13.6 eV
B.–6.8 eV
C.–27.2 eV
D.Zero
Solution
$P.E. = - 27.2 \times \frac{z^{2}}{n^{2}} = - 27.2eV$
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