Atomic StructureEasy
Question
What would be the approximate quantum number (n) for a circular orbit of hydrogen, 1 × 10–5 cm in diameter?
Options
A.31
B.43
C.40
D.39
Solution
$r_{n,z} = 0.529 \times \frac{n^{2}}{z}\overset{0}{A} \Rightarrow \frac{10^{- 5}}{2} = 0.529 \times \frac{n^{2}}{1} \times 10^{- 8} \Rightarrow n \approx 3$
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