Atomic StructureEasy
Question
Two electromagnetic radiations have wave numbers in the ratio 2: 3. Their energies per quanta will be in the ratio
Options
A.3: 2
B.9: 4
C.4: 9
D.2: 3
Solution
$E = n.h\bar{\upsilon} \Rightarrow E_{1}.E_{2} = \overline{\upsilon_{1}}:\overline{\upsilon_{2}} = 2:3$
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