Atomic StructureEasy
Question
The following charged particles accelerated from rest through the same potential difference are projected towards gold nucleus in different experiments. The distance of closest approach will be maximum for
Options
A.α–particle
B.proton
C.deuteron
D.same for all
Solution
$r = \frac{K.q_{1}q_{2}}{q_{1}V} = \frac{K.q_{2}}{V} = \text{ Constant}$
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