Atomic StructureHard
Question
The ratio of spacing between the third and fourth orbit to the spacing between sixth and seventh orbit of H–atom is
Options
A.7: 13
B.13: 7
C.16: 49
D.1: 1
Solution
$\frac{r_{4} - r_{3}}{r_{7} - r_{6}} = \frac{r_{1} \times 4^{2} - r_{1} \times 3^{2}}{r_{1} \times 7^{2} - r_{1} \times 6^{2}} = \frac{7}{13}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Light of wavelength λ, falls on a metal having work function hc/λ0. Photoelectric effect will take place only if...The circumference of the third orbit of He+ ion is x m. The de Broglie wavelength of electron revolving in this orbit wi...In the absence of external magnetic field, d-orbital is...An amount of 1.75 × 10–4 mole of HI decomposes by the absorption of photons of wavelength 2500 Å. If one molecule is dec...An isotone of is :...