Atomic StructureHard
Question
Last line of Lyman series for H-atom has wavelength λ1
, 2nd line of Balmer series has wavelength λ2 Å then
, 2nd line of Balmer series has wavelength λ2 Å then Options
A.
B.
C.
D.
Solution
= R(1)2 
and 
= R(1)2 
∴ λ1 =
and λ2 = 
∴
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