Atomic StructureHard
Question
The magnitude of the orbital angular momentum of an electron is given by $L = \sqrt{5}h/\pi$. How many orbitals of this kind are possible, belonging to an orbit?
Options
A.4
B.5
C.11
D.9
Solution
$L = \sqrt{l + (l + 1)}.\frac{h}{2\pi} = \sqrt{5}.\frac{h}{\pi} \Rightarrow l = 4$
Number of orbitals = 2$l$ + 1 = 9
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