Atomic StructureHard
Question
If E1, E2 and E3 are the kinetic energies of an electron, an α-particle and a proton with the same de Broglie wavelength, then
Options
A.E1 > E3 > E2
B.E2 > E3 > E1
C.E1 > E2 > E3
D.E1 = E2 = E3
Solution
$\lambda = \frac{h}{\sqrt{2mE}} \Rightarrow E \propto \frac{1}{m}\left( \text{for same }\lambda \right)$
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