Atomic StructureHard
Question
If the radius of first Bohr orbit is x unit, then de Broglie wavelength of electron in the third orbit is
Options
A.2πx unit
B.6πx unit
C.9x unit
D.18πx unit
Solution
$n\lambda = 2\pi r \Rightarrow \frac{2\pi \times x \times 3^{2}}{3} = 6\pi x$
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