Atomic StructureEasy
Question
The circumference of the third orbit of He+ ion is x m. The de Broglie wavelength of electron revolving in this orbit will be
Options
A.$\frac{x}{3}$m
B.3x m
C.$\frac{x}{9}$m
D.9x m
Solution
$2\pi r = n\lambda \Rightarrow x = 3 \times \lambda \Rightarrow \lambda = \frac{x}{3}m$
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