Atomic StructureHard

Question

When an electron de-excites from higher orbit in H-atom, two radiations are emitted out in Paschen and Lyman series. The wavelength of radiation emitted out in Lyman series is

Options

A.$\frac{8R}{9}$
B.$\frac{3R}{4}$
C.$\frac{4}{3R}$
D.$\frac{9}{8R}$

Solution

$\frac{1}{\lambda} = R \times 1^{2} \times \left( \frac{1}{1^{2}} - \frac{1}{3^{2}} \right) \Rightarrow \lambda = \frac{9}{8R}$

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