Atomic StructureHard

Question

If the mass of electron is doubled, the radius of first orbit of H-atom becomes approximately

Options

A.0.529 Å

B.0.265 Å

C.1.058 Å

D.0.32 Å

Solution

$r_{n,z} = \frac{\left( 4\pi\varepsilon_{o} \right)n^{2}h^{2}}{4\pi^{2}mze^{2}} \Rightarrow r_{n,z} \propto \frac{1}{m}$

∴ Radius of 1^st orbit of H-atom =$\overset{o}{A}$

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