The wavelength of the first line of the He+ ion spectral series whose interval between the extreme l

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The wavelength of the first line of the He+ ion spectral series whose interval between the extreme lines is 2.725 × 106 m–1 is (R = 1.09 × 107 m−1)

Accepted Answer

$\bar{\upsilon} = 2.725 	imes 10^{6} = 1.09 	imes 10^{7} 	imes 1^{2}\left( \frac{1}{(n + 1)^{2}} - \frac{1}{\infty^{2}} ight) $$${	herefore n = 3 }{	ext{Now, }\frac{1}{\lambda_{	ext{req}}} = 1.09 	imes 10^{7} 	imes 2^{2}\left( \frac{1}{3^{2}} - \frac{1}{4^{2}} ight) }{\Rightarrow \lambda_{	ext{req}} = 471.8	ext{ nm}}$$

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