Atomic StructureHard
Question
As the orbit number increases, the distance between two consecutive orbits (r1 = radius of first orbit)
Options
A.increases by 2r1.
B.increases by (2n – 1)r1, where n is the lower orbit number.
C.increases by (2n – 1)r1, where n is the higher orbit number.
D.remains constant.
Solution
$r_{n} = r_{1} \times r^{2}$
$\therefore r_{n} - r_{n - 1} = r_{1} \times n^{2} - r_{1}(n - 1)^{2} = (2n - 1).r_{1}$
Where n is the higher orbit.
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