Atomic StructureHard
Question
The dissociation energy of H2 is 429.0 kJ/mol. If H2 is dissociated by illumination with radiation of wavelength 270.0 nm, then what percentage of radiant energy will be converted into kinetic energy? (h = 6.6 × 10−34 J·s, NA = 6 × 1023)
Options
A.1.25%
B.2.5%
C.5.0%
D.7.5%
Solution
Energy absorbed per mole of H2
$6 \times 10^{23} \times \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{270 \times 10^{- 9}} \times 10^{- 3} = 440\text{ KJ}$
∴ Percentage of absorbed energy corrected into
$K.E. = \frac{440 - 429}{440} \times 100 = 2.5\%$
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