Atomic StructureHard

Question

The specific charges of two particles A and B are in the ratio 2: 3. If the mass ratio mA: mB is 2: 3, then the ratio of their charges eA: eB, is

Options

A.1: 1
B.4: 9
C.9: 4
D.2: 3

Solution

$\frac{\left( \frac{e}{m} \right)_{A}}{\left( \frac{e}{m} \right)_{B}} = \frac{e_{A}}{e_{B}} \times \frac{m_{B}}{m_{A}}$

$\Rightarrow \frac{2}{3} = \frac{e_{A}}{e_{B}} \times \frac{3}{2} \Rightarrow \frac{e_{A}}{e_{B}} = \frac{4}{9}$

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