Atomic StructureEasy
Question
The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is -
Options
A.5, 1, 1, + 1/2
B.6, 0, 0, + 1/2
C.5, 0, 0, + 1/2
D.5, 1, 0, + 1/2
Solution
37Rb = [Kr]5s1
Its valence electron is 5s1.
so, n = 5
Its valence electron is 5s1.
so, n = 5
l = 0 (For s orbitals)
m = 0 (As m = - l to + l )
s = +1/2
m = 0 (As m = - l to + l )
s = +1/2
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
What is the wave number of the radiation of lowest frequency in the Lyman series of the spectrum of Li2+ ion?...A radio station is emitting the radiations of frequency 2 × 104 Hz. If its frequency is doubled,...If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state c...Atoms have void spaces. It was first suggested by...Light of wavelength (λ) strikes a metal surface with intensity X and the metal emits Y electrons per second of maximum k...