Mole ConceptMedium
Question
The minimum mass of water needed to slake 1 kg of quicklime, assuming no loss by evaporation, is
Options
A.243.2 g
B.642.8 g
C.160.7 g
D.321.4 g
Solution
CaO + H2O → Ca(OH)2
56 g 18 g
$\therefore 1000g \frac{18}{56} \times 1000 = 321.4\text{ g}$
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