Mole ConceptMedium
Question
A quantity of 2.76 g of silver carbonate on being strongly heated yields a residue weighing (Ag = 108)
Options
A.2.16 g
B.2.48 g
C.2.32 g
D.2.64 g
Solution
2Ag2CO3 → 4Ag + 2CO2 ↑ + O2 ↑
2 × 276 g 4 × 108 g
$\therefore 2.76g \frac{4 \times 108}{2 \times 276} \times 2.76 = 2.16\text{ g}$
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