Mole ConceptMedium

Question

A quantity of 1.4 g of a hydrocarbon gives 1.8 g water on complete combustion. The empirical formula of hydrocarbon is

Options

A.CH
B.CH2
C.CH3
D.CH4

Solution

Mass per cent of hydrogen =$\frac{2}{18} \times \frac{1.8}{1.4} \times 100 = \frac{100}{7}$ and mass per cent of carbon =$100 - \frac{100}{7} = \frac{600}{7}$

Now, atomic ratio of C and H =$\frac{600/7}{12}:\frac{100/7}{1} = 1:2$

Hence, the empirical formula = CH2

Create a free account to view solution

View Solution Free
Topic: Mole Concept·Practice all Mole Concept questions

More Mole Concept Questions

From 2 mg calcium, 1.2 × 1019 atoms are removed. The number of g-atoms of calcium left is (Ca = 40)...A mixture of methane and ethylene in the ratio of a: b by volume occupies 30 ml. On complete combustion, the mixture yie...For CuSO4·5H2O, which is the correct mole relationship?...If NA is Avogadro′s number then number of valence electrons in 4.2 g of nitride ions (N3-)...The hourly energy requirement of an astronaut can be satisfied by the energy released when 34 g of sucrose (C12H22O11) a...