Mole ConceptHard

Question

A quantity of 1.4 g of a hydrocarbon gives 1.8 g water on complete combustion. The empirical formula of hydrocarbon is

Options

A.CH
B.CH2
C.CH3
D.CH4

Solution

Mass per cent of hydrogen =$\frac{2}{18} \times \frac{1.8}{1.4} \times 100 = \frac{100}{7}$ and mass per cent of carbon =$100 - \frac{100}{7} = \frac{600}{7}$

Now, atomic ratio of C and H =$\frac{600/7}{12}:\frac{100/7}{1} = 1:2$

Hence, the empirical formula = CH2

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